1348=2x^2+22x+304

Solution for 1348=2x^2+22x+304 equation:

1348=2x^2+22x+304

We move all terms to the left:

1348-(2x^2+22x+304)=0

We get rid of parentheses

-2x^2-22x-304+1348=0

We add all the numbers together, and all the variables

-2x^2-22x+1044=0

a = -2; b = -22; c = +1044;
Δ = b2-4ac
Δ = -222-4·(-2)·1044
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-94}{2*-2}=\frac{-72}{-4}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+94}{2*-2}=\frac{116}{-4}
=-29
$